Hammer Question?

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   I was wondering if any of you physics type guys could tell me how much it would effect the distances on my light hammer when my trainin hammer weighs 17# on the dot but its a steel bar with 2 5# weights. so the weight is distibuted all throughout the implement not just at the head. My PR in the light hammer is 102' with this hammer i was throwin 91ish? any thoughts?

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The_Murph Members Profile Send Private Message Find Members Posts Add to Buddy List Senior Member Joined: 8/13/09 Location: United States Status: Offline Points: 215	Post Options Post Reply Quote The_Murph Report Post Thanks(0) Quote Reply Topic: Hammer Question? Posted: 4/29/10 at 1:00pm
	I was wondering if any of you physics type guys could tell me how much it would effect the distances on my light hammer when my trainin hammer weighs 17# on the dot but its a steel bar with 2 5# weights. so the weight is distibuted all throughout the implement not just at the head. My PR in the light hammer is 102' with this hammer i was throwin 91ish? any thoughts?
	"perfect is the enemy of good"

Alan H Members Profile Send Private Message Find Members Posts Add to Buddy List Postaholic Account banned. Joined: 5/19/08 Status: Offline Points: 3135	Post Options Post Reply Quote Alan H Report Post Thanks(0) Quote Reply Posted: 4/29/10 at 4:58pm
	It would be pretty easy to calculate the difference in angular momentum between the two hammers for a given head velocity, at least if you were a calculus whiz but then figuring out how far it would go...well, it depends on other things, like for example, the angle of release.

mthompson33 Members Profile Send Private Message Find Members Posts Add to Buddy List Postaholic Joined: 8/27/09 Location: United States Status: Offline Points: 1369	Post Options Post Reply Quote mthompson33 Report Post Thanks(0) Quote Reply Posted: 4/30/10 at 7:22am
	For simplicity, I think you have to assume the same angle of release for both hammers and no air drag. Thus the difference in distance is a ratio of the velocity of the CG at release. The big difference is the radius of the CG (how far the CG is from your center of rotation). I don't know if you can assume equal head velocity, because of the variation in weight and rotational moment of inertia. The best correlations I have done involved equal energy being input in to the implements. This should provide a reasonable "knock down" for the practice implement.
	Matt Thompson "If you wake up and you're not in pain, you know you're dead." -- Russian Proverb

Duncan McCallum Members Profile Send Private Message Find Members Posts Add to Buddy List Postaholic Joined: 12/07/07 Location: United States Status: Offline Points: 7442	Post Options Post Reply Quote Duncan McCallum Report Post Thanks(0) Quote Reply Posted: 5/24/10 at 8:08pm
	Yeah, what Matt said... Shut up Murph...you're going to be fine.
	The man in the arena.